English
Fix a ≠ 0; the map z ↦ z^b is continuous at any b in the exponent when considering base a; equivalently, z ↦ a^z is continuous at z = b.
Русский
Пусть a ≠ 0; отображение z ↦ z^b непрерывно в точке z = b при основании a, т.е. a^z непрерывно по z в точке b.
LaTeX
$$$$\\text{If } a \\neq 0,\\quad z \\mapsto z^{b} \\text{ is continuous at } z=a.$$$$
Lean4
theorem continuousAt_const_cpow {a b : ℂ} (ha : a ≠ 0) : ContinuousAt (fun x : ℂ => a ^ x) b :=
by
have cpow_eq : (fun x : ℂ => a ^ x) = fun x => exp (log a * x) :=
by
ext1 b
rw [cpow_def_of_ne_zero ha]
rw [cpow_eq]
exact continuous_exp.continuousAt.comp (ContinuousAt.mul continuousAt_const continuousAt_id)