English
For differentiable f within s and with f(x) ≠ 0, the derivative within sqrt(f) satisfies derivWithin sqrt(f) = derivWithin f / (2√f).
Русский
Для дифференцируемой внутри s функции f, при f(x) ≠ 0, производная внутри sqrt(f) равна derivWithin f /(2√f).
LaTeX
$$$$ \operatorname{derivWithin}(\sqrt{f}, s, x) = \frac{\operatorname{derivWithin}(f, s, x)}{2\sqrt{f(x)}}. $$$$
Lean4
theorem derivWithin_sqrt (hf : DifferentiableWithinAt ℝ f s x) (hx : f x ≠ 0) (hxs : UniqueDiffWithinAt ℝ s x) :
derivWithin (fun x => √(f x)) s x = derivWithin f s x / (2 * √(f x)) :=
(hf.hasDerivWithinAt.sqrt hx).derivWithin hxs