English
If Archimedean R and 0 ≤ a < 1, then arithGeom(a,b,u0) tends to b/(1-a) as n → ∞.
Русский
Если R Архимедово, 0 ≤ a < 1, то arithGeom(a,b,u0) стремится к b/(1-a) при n → ∞.
LaTeX
$$0 \le a \land a < 1 \Rightarrow \lim_{n \to \infty} \mathrm{arithGeom}(a,b,u_0,n) = \frac{b}{1-a}$$
Lean4
theorem tendsto_arithGeom_nhds_of_lt_one [Archimedean R] [TopologicalSpace R] [OrderTopology R] (ha_pos : 0 ≤ a)
(ha : a < 1) : Tendsto (arithGeom a b u₀) atTop (𝓝 (b / (1 - a))) :=
by
rw [arithGeom_eq' ha.ne]
conv_rhs => rw [← zero_add (b / (1 - a))]
refine Tendsto.add ?_ tendsto_const_nhds
conv_rhs => rw [← zero_mul (u₀ - (b / (1 - a)))]
exact (tendsto_pow_atTop_nhds_zero_of_lt_one ha_pos ha).mul_const _