English
Transport HasExactColimitsOfShape along a domain equivalence of shapes J ≃ J'.
Русский
Переноc HasExactColimitsOfShape вдоль эквивалентности формы J ≃ J'.
LaTeX
$$$\text{HasExactColimitsOfShape}(J',C)$ from $\text{HasExactColimitsOfShape}(J,C)$ via a domain equivalence $J\simeq J'$$$
Lean4
/-- Transport a `HasExactLimitsOfShape` along an equivalence of the shape.
Note: When `C` has finite colimits, this lemma holds with the equivalence replaced by a initial
functor, see `hasExactLimitsOfShape_of_initial` below.
-/
theorem of_domain_equivalence {J J' : Type*} [Category J] [Category J'] (e : J ≌ J') [HasLimitsOfShape J C]
[HasExactLimitsOfShape J C] :
haveI : HasLimitsOfShape J' C := hasLimitsOfShape_of_equivalence e
HasExactLimitsOfShape J' C :=
haveI : HasLimitsOfShape J' C := hasLimitsOfShape_of_equivalence e
⟨preservesFiniteColimits_of_natIso (Functor.Initial.limIso e.functor)⟩