English
In a short exact sequence S, if X₁ has pdLT n and X₂ has pdLT (n+1), then X₃ has pdLT (n+1).
Русский
В короткой точной последовательности S, если X₁ имеет pdLT n, а X₂ — pdLT (n+1), то X₃ имеет pdLT (n+1).
LaTeX
$$$\forall S.S.ShortExact\Rightarrow \forall n:\mathbb{N}, HasProjectiveDimensionLT(S.X_1, n) \rightarrow HasProjectiveDimensionLT(S.X_2, n+1) \rightarrow HasProjectiveDimensionLT(S.X_3, n+1)$$$
Lean4
theorem hasProjectiveDimensionLT_X₃ (h₁ : HasProjectiveDimensionLT S.X₁ n)
(h₂ : HasProjectiveDimensionLT S.X₂ (n + 1)) : HasProjectiveDimensionLT S.X₃ (n + 1) :=
by
letI := HasExt.standard C
rw [hasProjectiveDimensionLT_iff]
rintro (_ | i) hi Y x₃
· simp at hi
· obtain ⟨x₁, rfl⟩ :=
Ext.contravariant_sequence_exact₃ hS _ x₃ (Ext.eq_zero_of_hasProjectiveDimensionLT _ (n + 1) hi) (add_comm _ _)
rw [x₁.eq_zero_of_hasProjectiveDimensionLT n (by cutsat), Ext.comp_zero]