English
If a morphism is an epi, it is surjective on pseudoelements; conversely surjectivity implies epi.
Русский
Если морфизм является эпиморфизмом, он сюръективен на псевдоэлементах; наоборот сюръективность имплицитно эквивалентна эпи.
LaTeX
$$$\\text{epi}(f) \\iff \\mathrm{pseudo_surjective}(f)$$$
Lean4
/-- An epimorphism is surjective on pseudoelements. -/
theorem pseudo_surjective_of_epi {P Q : C} (f : P ⟶ Q) [Epi f] : Function.Surjective f := fun qbar =>
Quotient.inductionOn qbar fun q =>
⟨(pullback.fst f q.hom : Over P),
Quotient.sound <|
⟨pullback f q.hom, 𝟙 (pullback f q.hom), pullback.snd _ _, inferInstance, inferInstance, by
rw [Category.id_comp, ← pullback.condition, app_hom, Over.coe_hom]⟩⟩