English
The restriction functor is full when the homomorphism f is surjective.
Русский
Ограничение полно, если гомоморфизм f сюръективен.
LaTeX
$$full_res (f_surj : Function.Surjective f) : (res V f).Full$$
Lean4
/-- The functor from `Action V H` to `Action V G` induced by a morphism `f : G → H` is full
if `f` is surjective. -/
theorem full_res (f_surj : Function.Surjective f) : (res V f).Full where
map_surjective {X} {Y}
g := by
use ⟨g.hom, fun h ↦ ?_⟩
· ext
simp
· obtain ⟨a, rfl⟩ := f_surj h
have : X.ρ (f a) = ((res V f).obj X).ρ a := rfl
rw [this, g.comm a]
simp