English
There is a natural equivalence between morphisms G ⟶ F' and L ⋙ G ⟶ F, given α and F' with the IsRightKanExtension property.
Русский
Существует естественное эквивалентность между морфизмами G ⇢ F' и L ⋙ G ⇢ F, заданная α и F' с свойством IsRightKanExtension.
LaTeX
$$$ (G \\to F') \\simeq (L \\circ G \\to F) $ (via the canonical hom-set isomorphism).$$
Lean4
/-- If `(F', α)` is a right Kan extension of `F` along `L`, then this
is the induced bijection `(G ⟶ F') ≃ (L ⋙ G ⟶ F)` for all `G`. -/
noncomputable def homEquivOfIsRightKanExtension (G : D ⥤ H) : (G ⟶ F') ≃ (L ⋙ G ⟶ F)
where
toFun β := whiskerLeft _ β ≫ α
invFun β := liftOfIsRightKanExtension _ α _ β
left_inv β := Functor.hom_ext_of_isRightKanExtension _ α _ _ (by simp)
right_inv := by cat_disch