English
For X,Y and LeftFraction z1,z2, equality of their images under a localization functor L is equivalent to LeftFractionRel z1 z2.
Русский
Для x,y и левых дробей z1,z2 равенство их изображений под локализационным функтором L эквивалентно LeftFractionRel z1 z2.
LaTeX
$$$\forall {C} {D} [\text{Category } C] [\text{Category } D] {W} {X Y} (z_1 z_2 : W.LeftFraction X Y) (L : C \to D) [L.IsLocalization W],
\; homMk z_1 = homMk z_2 \;\Leftrightarrow\; LeftFractionRel z_1 z_2$$$
Lean4
theorem map_eq_iff {X Y : C} (f g : LeftFraction W X Y) :
f.map (LeftFraction.Localization.Q W) (Localization.inverts _ _) =
g.map (LeftFraction.Localization.Q W) (Localization.inverts _ _) ↔
LeftFractionRel f g :=
by
simp only [← Hom.map_mk _ (Q W)]
constructor
· intro h
rw [← homMk_eq_iff_leftFractionRel, homMk_eq, homMk_eq]
exact h
· intro h
congr 1
exact Quot.sound h