English
Explicit form of the inverse component of the iso adjunction is given by a long explicit composition of shifted maps and unit/counit components.
Русский
Явное выражение обратной компоненты изоморфизма сопряжения через длинную явную композицию сдвигов и единицы/кавиности.
LaTeX
$$$ (\mathrm{iso}(\mathrm{adj}, a))^{-1}_{Y} = \text{long composition of shifted maps and unit/counit}$$$
Lean4
@[reassoc]
theorem iso_inv_app (Y : D) :
(iso adj a).inv.app Y =
adj.unit.app ((shiftFunctor C a).obj (G.obj Y)) ≫
G.map ((shiftFunctorCompIsoId D b a h).inv.app (F.obj ((shiftFunctor C a).obj (G.obj Y)))) ≫
G.map ((shiftFunctor D a).map ((shiftFunctor D b).map ((F.commShiftIso a).hom.app (G.obj Y)))) ≫
G.map
((shiftFunctor D a).map
((shiftFunctorCompIsoId D a b (by rw [eq_neg_of_add_eq_zero_left h, add_neg_cancel])).hom.app
(F.obj (G.obj Y)))) ≫
G.map ((shiftFunctor D a).map (adj.counit.app Y)) :=
by
obtain rfl : b = -a := by rw [← add_left_inj a, h, neg_add_cancel]
simp only [iso, iso', shiftEquiv', Equiv.toFun_as_coe, conjugateIsoEquiv_apply_inv, conjugateEquiv_apply_app,
Functor.comp_obj, comp_unit_app, Functor.id_obj, Equivalence.toAdjunction_unit, Equivalence.Equivalence_mk'_unit,
Iso.symm_hom, Functor.comp_map, comp_counit_app, Equivalence.toAdjunction_counit,
Equivalence.Equivalence_mk'_counit, Functor.map_shiftFunctorCompIsoId_hom_app, assoc, Functor.map_comp]
slice_lhs 3 4 => rw [← Functor.map_comp, ← Functor.map_comp, Iso.inv_hom_id_app]
simp only [Functor.comp_obj, Functor.map_id, id_comp, assoc]