English
Let F: C ⥤ D with HasShift.induced structure via i; then (shiftFunctorZero D A).inv.app (F.obj X) equals F.map ((shiftFunctorZero C A).inv.app X) ≫ (i 0).inv.app X.
Русский
Пусть F: C ⥤ D с индуцированной структурой через i; тогда (shiftFunctorZero D A).inv.app (F.obj X) = F.map ((shiftFunctorZero C A).inv.app X) ≫ (i 0).inv.app X.
LaTeX
$$$(shiftFunctorZero D A).inv.app (F.obj X) = F.map ((shiftFunctorZero C A).inv.app X) \\circ (i 0).inv.app X$$$
Lean4
@[simp]
theorem shiftFunctorZero_inv_app_obj_of_induced (X : C) :
letI := HasShift.induced F A s i
(shiftFunctorZero D A).inv.app (F.obj X) = F.map ((shiftFunctorZero C A).inv.app X) ≫ (i 0).inv.app X :=
by simp only [ShiftMkCore.shiftFunctorZero_eq, HasShift.Induced.zero_inv_app_obj]