English
For any p, and a ∈ α, b, c ∈ β, a^{ite(p,b,c)} = ite(p, a^b, a^c).
Русский
Пусть p — произвольное высказывание; тогда для любых a ∈ α, b,c ∈ β верно: a^{ite(p,b,c)} = ite(p, a^b, a^c).
LaTeX
$$$a^{\mathrm{ite}(p,b,c)} = \mathrm{ite}(p, a^{b}, a^{c})$$$
Lean4
@[to_additive (attr := simp) ite_smul]
theorem pow_ite (p : Prop) [Decidable p] (a : α) (b c : β) : a ^ (if p then b else c) = if p then a ^ b else a ^ c :=
pow_dite _ _ _ _