English
For any p and a,b ∈ α, c ∈ β, (ite(p,a,b))^c = ite(p, a^c, b^c).
Русский
Пусть p — произвольное высказывание; тогда (ite(p,a,b))^c = ite(p, a^c, b^c).
LaTeX
$$$(\mathrm{ite}(p,a,b))^{c} = \mathrm{ite}(p, a^{c}, b^{c})$$$
Lean4
@[to_additive (attr := simp) smul_ite]
theorem ite_pow (p : Prop) [Decidable p] (a b : α) (c : β) : (if p then a else b) ^ c = if p then a ^ c else b ^ c :=
dite_pow _ _ _ _