English
The composition of an ofLE map with an ofLEMk map equals the ofLEMk map for the transitive composition of subobjects.
Русский
Сложение ofLE и ofLEMk равно to mk движению по трём подобъектам: h1.trans h2.
LaTeX
$$$\operatorname{ofLE} X Y h_1 \;\circ\; \operatorname{ofLEMk} Y f h_2 = \operatorname{ofLEMk} X f (h_1 \trans h_2)$$$
Lean4
@[reassoc (attr := simp)]
theorem ofLE_comp_ofLEMk {B A : C} (X Y : Subobject B) (f : A ⟶ B) [Mono f] (h₁ : X ≤ Y) (h₂ : Y ≤ mk f) :
ofLE X Y h₁ ≫ ofLEMk Y f h₂ = ofLEMk X f (h₁.trans h₂) :=
by
simp only [ofLEMk, ofLE, ← Functor.map_comp_assoc underlying]
congr 1