English
If s is complemented, then the piecewise with f,g is equal to the left-right swapped version on the complement: (s^c).piecewise f g = s.piecewise g f.
Русский
Для дополнения множества верна перестановка ветвей: (s^c).piecewise f g = s.piecewise g f.
LaTeX
$$$$\\bigl(s^{c}\\bigr).piecewise f g = s.piecewise g f.$$$$
Lean4
theorem piecewise_compl [DecidableEq ι] (s : Finset ι) [∀ i, Decidable (i ∈ s)] [∀ i, Decidable (i ∈ sᶜ)]
(f g : ∀ i, π i) : sᶜ.piecewise f g = s.piecewise g f :=
by
ext i
simp [piecewise]