English
In a nonassociative ring R, for all a,b ∈ R and k ∈ ℕ, (-1)^k a b = (-1)^k (a b).
Русский
В нерегулярном кольце R для любых a,b ∈ R и натурального k выполняется (-1)^k a b = (-1)^k (a b).
LaTeX
$$$ (-1)^k \cdot a \cdot b = (-1)^k \cdot (a \cdot b) $$$
Lean4
theorem neg_npow_assoc {R : Type*} [NonAssocRing R] [Pow R ℕ] [NatPowAssoc R] (a b : R) (k : ℕ) :
(-1) ^ k * a * b = (-1) ^ k * (a * b) := by
induction k with
| zero => simp only [npow_zero, one_mul]
| succ k ih =>
rw [npow_add, npow_one, ← neg_mul_comm, mul_one]
simp only [neg_mul, ih]