English
For arbitrary indices m ≤ n, if m ≠ 0, then #(s^m) ≤ #(s^n).
Русский
Для каких-либо m ≤ n, если m ≠ 0, то #(s^m) ≤ #(s^n).
LaTeX
$$$$ (\forall m,n \in \mathbb{N})\; (m \neq 0) \land (m \le n) \Rightarrow #(s^m) \le #(s^n). $$$$
Lean4
/-- See `Finset.Nonempty.card_pow_mono` for a version that works for zero powers. -/
@[to_additive /-- See `Finset.Nonempty.card_nsmul_mono` for a version that works for zero scalars. -/
]
theorem card_pow_mono (hm : m ≠ 0) (hmn : m ≤ n) : #(s ^ m) ≤ #(s ^ n) :=
by
obtain rfl | hs := s.eq_empty_or_nonempty
· simp [hm]
· exact hs.card_pow_mono hmn